The problem is with your current density $vec{j}$, let's start with it's basic definition as current over area, $vec{j} = frac{Qvec{v}}{4pi R^2}$, now knowing that the angular velocity can be used to get the linear velocity of the charge on the spherical surface using $vec{v}=vec{omega}times Rhat{r} = omega R hat{z} times hat{r} = omega R (costhetahat{r}-sinthetahat{theta ...
بیشتر25. 4. Homework Statement: inside a cylinder (not solid) with radius and infinite lengh there is a charge with uniform density . the charge rotating inside the cylinder in speed. find the vector of magnetic field inside the cylinder. Relevant Equations:
بیشترCylindrical hollow magnetron with reflecting surface; Figure 3. Basic cylindrical post magnetron configuration and associated magnetic field [2]. One of the problems with this geometry is that the magnetic field and thus the deposition rate falls off at the ends of the tube and can actually accumulate material sputtered from the interior section.
بیشترHomework Statement. The problem is to find the magnetic field within a rotating cylinder (infinitely long) that has on its surface a given surface charge density p. I made a picture of the problem to illustrate this. The only hint given: "the magnetic field outside the cylinder is zero.
بیشترModeling the interaction of a slowly rotating hollow conducting sphere in a magnetic field provided an understanding of the dynamics of orbiting space objects moving through the Earth's magnetic field.
بیشترIn this paper, the natural frequencies of the radial vibrations of a hollow cylinder with different boundary conditions under influences of magnetic field, rotation and non-homogeneity have been studied. The solution of the problem is obtained by using technique of variables separation. In the present paper three different boundary conditions are considered, namely the free, fixed and mixed ...
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بیشترA Appendix: Rotating Spherical Shell of Charge The case of a spherical shell of radius a with uniform surface density of electric charge in rotation at angular velocity ω about, say, the z-axis has been considered in [14].For total charge Q the electric field in the lab frame is, in spherical coordinates (r,θ,φ), E(ra)=Q r2 ˆr, (11) independent of the angular velocity ω, while ...
بیشترIn contrast, magnetic field lines always form close loop, as magnetic charges do not exist (as far as we know). Hence, it is less clear that the magnetic field lines rotate along with the charged cylinder. Indeed, Faraday's view (secs. 218 and 220 of [10], and sec. 3090 of [11]) was that the magnetic field lines do not rotate in this case.2
بیشترand therefore the magnetic flux density in the non-hollow portion of the cylinder is: () 22 0 0 r for 2 b aJ b cφ µ ρ ρ ρ ⎛⎞− =<<⎜⎟ ⎝⎠ B ˆ ρ>c Note that outside the cylinder (i.e., ρ>c), the current density J()r is again zero, and therefore: () () 00 0 0 0 22 0 22 0 00 00 22 …
بیشترA hollow cylinder of length L and radius R, is madeout of a non-conducting material, is charged with a constant surface charge σ, and is rotating, along its axis of symmetry, with an angular velocity w(t) = αt. Q:What is the magnetic field inside the cylinder? Homework Equations Maxwell correction for Ampere law. The Attempt at a Solution
بیشتر2The case of an infinite cylinder made of a good conductor with relative permeability μ is considered in probs. 7.30-38 of [1], and in sec. 5.7 of [2]. Much of the technical literature on this theme emphasizes hollow cylinders of finite length; see, for example [3]-[6]. Rotating spheres and ellipsoidsare discussed in …
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بیشترI need to find out what is the magnetic field inside a rotating long cylinder with a charged density σ. The cylinder rotates around its axis with angular speed ω. All of the parameters are constants. I've tried using Amper's law but I can't seem to get to the right answer. J = λ ⋅ v = σ ω R d r.
بیشترThe magnetization A/m (remanent field ). Consider the hollow cylindrical magnet as two cylindrical magnets with radii and, of equal length and magnetization. The magnetization directions of the cylinders are opposite. Therefore the magnetic field induction is calculated as the total of two cylindrical magnetic inductions .
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